本文實例講述了python實現在無須過多援引的情況下創建字典的方法。分享給大家供大家參考。具體實現方法如下：

1.使用itertools模塊

import itertoolsthe_key = ['ab','22',33]the_vale = ['aaaa',"dddddddd",'22222222222']d = dict(itertools.izip(the_key,the_vale))print d

2.加參數

dict = dict(red = 1,bule = 2,yellow = 3)print dict

結果為：{'yellow': 3, 'bule': 2, 'red': 1}

3.使用內置的zip函數
zip([iterable,...])返回一個列表，

the_key = ['ab','22',33]the_vale = ['aaaa',"dddddddd",'22222222222']dict2 = dict(zip(the_key,the_vale))print type(zip(the_key,the_vale))print dict2

結果：

<type 'list'>{33: '22222222222', 'ab': 'aaaa', '22': 'dddddddd'}

4.dict的fromkeys函數
創建的每個鍵有相同的value

fromkeys(seq[,value])Create a new dictionary with keys from seq and values set to value.the_key = ['ab','22',33]the_vale = 0d = dict.fromkeys(the_key,the_vale)print 

結果：{33: 0, 'ab': 0, '22': 0}

import stringcount_by_letter = dict.fromkeys(string.ascii_lowercase,0)print count_by_letter

結果：

{'a': 0, 'c': 0, 'b': 0, 'e': 0, 'd': 0, 'g': 0, 'f': 0, 'i': 0, 'h': 0, 'k': 0, 'j': 0, 'm': 0, 'l': 0, 'o': 0, 'n': 0, 'q': 0, 'p': 0, 's': 0, 'r': 0, 'u': 0, 't': 0, 'w': 0, 'v': 0, 'y': 0, 'x': 0, 'z': 0}

希望本文所述對大家Python程序設計的學習有所幫助。