廢話不多說(shuō)，估計(jì)只有我這個(gè)菜鳥(niǎo)廢了2個(gè)小時(shí)才搞出來(lái)，主要是我想了太多方法來(lái)實(shí)現(xiàn)，最后都因?yàn)檫@因?yàn)槟堑脑蚴×?/p>

間接說(shuō)明自己對(duì)可變與不可變類型的了解，還是不夠透徹

最后就用了個(gè)笨方法解決了！

#coding:utf-8import xlrdimport xlwtimport osfrom collections import Counterworkbook = xlrd.open_workbook(r'D:/hh/heli/a.xlsx')Sheet1 = workbook.sheet_by_name('Sheet1')clos_a=Sheet1.col_values(1)clos_b=Sheet1.col_values(4)clos_c=Sheet1.col_values(5)wbk = xlwt.Workbook()sheet = wbk.add_sheet(u'初始表')sheet.write(0, 0, u'小區(qū)')sheet.write(0, 1, u'總端口數(shù)')sheet.write(0, 2, u'已使用端口數(shù)')test=('D:/hh/heli//美女你好.xls').decode('utf-8') #表名是不是讓你想入非非了，哈哈result = []list_m=map(lambda x,y:[x,y],clos_a,clos_b)list_n=map(lambda q,w:[q,w],clos_a,clos_c)dic={}dic_a={}def read_excel():  while test is True:    os.remove(test)  else:    for elem in list_m:      key=elem[0]      if key in dic:        dic[key]+=elem[1]      else:        dic[key]=elem[1]    for elem_a in list_n:      key_a = elem_a[0]      if key_a in dic_a:        dic_a[key_a]+=elem_a[1]      else:        dic_a[key_a] = elem_a[1]  item=list(dic)  item_a=list(dic_a)  for i in range(1,len(item)):    sheet.write(i,0,item[i])    sheet.write(i,1,dic[item[i]])  for p in range(1,len(item_a)):    sheet.write(p,2,dic_a[item_a[p]])  wbk.save(test)if __name__ == "__main__":  read_excel()

以上這篇python對(duì)excel文檔去重及求和的實(shí)例就是小編分享給大家的全部?jī)?nèi)容了，希望能給大家一個(gè)參考，也希望大家多多支持武林站長(zhǎng)站。