本文實例講述了Python實現嵌套列表及字典并按某一元素去重復功能。分享給大家供大家參考,具體如下:
#! /usr/bin/env python#coding=utf-8class HostScheduler(object): def __init__(self, resource_list): self.resource_list = resource_list def MergeHost(self): allResource=[] allResource.append(self.resource_list[0]) for dict in self.resource_list: #print len(l4) k=0 for item in allResource: #print 'item' if dict['host'] != item['host']: k=k+1 #continue else: break if k == len(allResource): allResource.append(dict) taskhost=[] for item in allResource: taskhost.append(item['host']) return taskhost#該函數實現嵌套列表中,按某一元素去重復def deleteRepeat(): #1、列表中嵌套列表。按元素‘b'實現去重復 l1=[['b',1],['b',2],['c',3],['a',1],['b',1],['b',1],] l2=[] l2.append(l1[0]) for data in l1: #print len(l2) k=0 for item in l2: #print 'item' if data[0] != item[0]: k=k+1 else: break if k == len(l2): l2.append(data) print "l2: ",l2 #2、列表中嵌套字典。按鍵值host實現去重復 l3=[{'host':'compute21', 'cpu':2},{'host':'compute21', 'cpu':2},{'host':'compute22', 'cpu':2}, {'host':'compute23', 'cpu':2},{'host':'compute22', 'cpu':2},{'host':'compute23', 'cpu':2}, {'host':'compute24', 'cpu':2}] l4=[] l4.append(l3[0]) for dict in l3: #print len(l4) k=0 for item in l4: #print 'item' if dict['host'] != item['host']: k=k+1 #continue else: break if k == len(l4): l4.append(dict) print "l4: ",l4if __name__ == '__main__': #deleteRepeat() resource_list=[{'host':'compute21', 'cpu':2},{'host':'compute21', 'cpu':2},{'host':'compute22', 'cpu':2}, {'host':'compute23', 'cpu':2},{'host':'compute22', 'cpu':2},{'host':'compute23', 'cpu':2}, {'host':'compute24', 'cpu':2}] hostSchedule=HostScheduler(resource_list) taskhost=hostSchedule.MergeHost() print '武林站長站測試結果: ' print 'taskhost: ' print taskhost運行結果:

PS:本站還有兩款比較簡單實用的在線文本去重復工具,推薦給大家使用:
在線去除重復項工具:
http://tools.jb51.net/code/quchong
在線文本去重復工具:
http://tools.jb51.net/aideddesign/txt_quchong
更多關于Python相關內容可查看本站專題:《Python字典操作技巧匯總》、《Python字符串操作技巧匯總》、《Python常用遍歷技巧總結》、《Python數據結構與算法教程》、《Python函數使用技巧總結》及《Python入門與進階經典教程》
希望本文所述對大家Python程序設計有所幫助。
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