這個跟ping那個差不多,ping的那個腳本就是通過這個改了下,大體一致,不過telnet的不需要判斷返回的字符串??煲恍?/p>
這里具體需要telnet的ip是需要自己向定義好的數組中寫的
我這里加了一個定時,是7200秒,也就是2小時
行了,上代碼吧:
#!/usr/bin/env python# coding: utf8 import telnetlibimport timeimport codecsimport os # telnet hostdef telnetdo(host, statusFile): status1 = 'telnet success' status2 = 'telnet faild' for ipAdd in host: # get now time nowTime = time.strftime('%Y-%m-%d %H:%M:%S',time.localtime(time.time())) try: t = telnetlib.Telnet(ipAdd, port=23, timeout=1) writeToText(nowTime, ipAdd, status1, statusFile) except: writeToText(nowTime, ipAdd, status2, statusFile) # write status information to txtdef writeToText(nowTime, ipAdd, status, statusFile): s_text = 'TIME:' + nowTime + '/t' + 'IP:' + ipAdd + '/t' + 'STATUS:' + status + '/r/n' if '0' == judgeFile(statusFile): with open(statusFile, 'a') as f: f.write(s_text) f.close() if '1' == judgeFile(statusFile): with open(statusFile, 'w') as f: f.write(s_text) f.close() # Determine whether statusFile exists # 0: exists# 1: no existsdef judgeFile(statusFile): if os.path.exists(statusFile): return '0' else: return '1' if __name__ == "__main__": host = ['192.168.1.254', '192.168.1.100'] # write file statusFile = '/root/telnetStatus.txt' i = 7200 while i: telnetdo(host, statusFile) time.sleep(2) i = i - 1結果會存在/root下面
以上這篇Python判斷telnet通不通的實例就是小編分享給大家的全部內容了,希望能給大家一個參考,也希望大家多多支持武林站長站。
新聞熱點
疑難解答