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opencv實現靜態手勢識別 opencv實現剪刀石頭布游戲

2020-02-16 00:49:55
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本文實例為大家分享了opencv實現靜態手勢識別的具體代碼,供大家參考,具體內容如下

要想運行該代碼,請確保安裝了:python 2.7,opencv 2.4.9

效果如下:


算法如下:

把圖片先進行處理,處理過程:

     1.用膨脹圖像與腐蝕圖像相減的方法獲得輪廓。

     2.用二值化獲得圖像

     3. 反色

經過如上的處理之后,圖片為:

這之后就簡單了,設計一個辦法把三種圖像區分開來即可。

代碼如下:

# -*- coding: cp936 -*-import cv2import numpyimport timeimport randomimport osdef judge( ): #構造一個3×3的結構元素 # return 0 stone ,1 jiandao, 2 bu img = cv2.imread("wif.jpg",0) element = cv2.getStructuringElement(cv2.MORPH_RECT,(11,11)) dilate = cv2.dilate(img, element) erode = cv2.erode(img, element) #將兩幅圖像相減獲得邊,第一個參數是膨脹后的圖像,第二個參數是腐蝕后的圖像 result = cv2.absdiff(dilate,erode); #上面得到的結果是灰度圖,將其二值化以便更清楚的觀察結果 retval, result = cv2.threshold(result, 40, 255, cv2.THRESH_BINARY);  #反色,即對二值圖每個像素取反 result = cv2.bitwise_not(result); result =cv2.medianBlur(result,23) a=[] posi =[] width =[] count = 0 area = 0  for i in range(result.shape[1]): for j in range(result.shape[0]):  if(result[j][i]==0):  area+=1 for i in range(result.shape[1]): if(result[5*result.shape[0]/16][i]==0 and result[5*result.shape[0]/16][i-1]!=0 ):  count+=1  width.append(0)  posi.append(i) if(result[5*result.shape[0]/16][i]==0):  width[count-1]+=1 """ print 'the pic width is ',result.shape[1],'/n' for i in range(count): print 'the ',i,'th',' ','is'; print 'width ',width[i] print 'posi ',posi[i],'/n' print count,'/n' print 'area is ',area,'/n'  cv2.line(result,(0,5*result.shape[0]/16),(214,5*result.shape[0]/16),(0,0,0)) cv2.namedWindow("fcuk") cv2.imshow("fcuk",result) cv2.waitKey(0) """ #判定時間  width_length=0 width_jiandao = True for i in range(count): if width[i]>45:  #print 'bu1';  return 2; if width[i]<=20 or width[i]>=40:  width_jiandao= False width_length += width[i] if width_jiandao==True and count==2: return 1; if(area <8500): #print 'shi tou'; return 0; print "width_leng",width_length if(width_length<35): #這個時候說明照片是偏下的,所以需要重新測定。 a=[] posi =[] width =[] count = 0 for i in range(result.shape[1]):  if(result[11*result.shape[0]/16][i]==0 and result[11*result.shape[0]/16][i-1]!=0 ):  count+=1  width.append(0)  posi.append(i)  if(result[11*result.shape[0]/16][i]==0):  width[count-1]+=1 """ print 'the pic width is ',result.shape[1],'/n' for i in range(count):  print 'the ',i,'th',' ','is';  print 'width ',width[i]  print 'posi ',posi[i],'/n' print count,'/n' print 'area is ',area,'/n' """ width_length=0 width_jiandao = True for i in range(count): if width[i]>45:  #print 'bu1';  return 2; if width[i]<=20 or width[i]>=40:  width_jiandao= False width_length += width[i] if width_jiandao==True and count==2: return 1; if(area>14000 or count>=3): #print 'bu2'; return 2; if(width_length<110): #print 'jian dao'; return 1; else: #print 'bu3'; return 2;  """print("這是通過攝像頭來玩的剪刀石頭布的游戲,輸入y開始/n")s = raw_input()capture = cv2.VideoCapture(0)cv2.namedWindow("camera",1)start_time = time.time()print("給你5秒的時間把手放到方框的位置/n")while(s=='y' or s=='Y'): ha,img =capture.read() end_time = time.time() cv2.rectangle(img,(426,0),(640,250),(170,170,0)) cv2.putText(img,str(int((5-(end_time- start_time)))), (100,100), cv2.FONT_HERSHEY_SIMPLEX, 2, 255) cv2.imshow("camera",img)  if(end_time-start_time>5): break if(cv2.waitKey(30)>=0): breakha,img = capture.read()capture.release()cv2.imshow("camera",img)img = img[0:210,426:640]cv2.imwrite("wif.jpg",img)judge() cv2.waitKey(0)print "fuck""""def game(): fuck =[] fuck.append("石頭") fuck.append("剪刀") fuck.append("布") capture = cv2.VideoCapture(0) cv2.namedWindow("camera",1) start_time = time.time() print("給你5秒的時間把手放到方框的位置/n") while(1): ha,img =capture.read() end_time = time.time() cv2.rectangle(img,(426,0),(640,250),(170,170,0)) cv2.putText(img,str(int((5-(end_time- start_time)))), (100,100), cv2.FONT_HERSHEY_SIMPLEX, 2, 255) cv2.imshow("camera",img) if(end_time-start_time>5):  break if(cv2.waitKey(30)>=0):  break ha,img = capture.read() capture.release() cv2.imshow("camera",img) img = img[0:210,426:640] cv2.imwrite("wif.jpg",img) p1 = judge() pc = random.randint(0,2) #print p1,' ',pc,'/n' print "你出的是",fuck[p1]," 電腦出的是",fuck[pc],"/n" cv2.destroyAllWindows() if(p1==pc): print "平局/n" return 0 if((p1==0 and pc ==1)or(p1==1 and pc ==2)or(p1==2 and pc ==0)): print '你贏了/n' return 1 else: print '你輸了/n' return -1def main(): you_win=0 pc_win=0 print("這是通過攝像頭來玩的剪刀石頭布的游戲,請輸入回車開始游戲/n") s = raw_input() while(1): print "比分(玩家:電腦) ",you_win,":",pc_win,'/n' s = raw_input() os.system('cls') ans =game() if(ans == 1):  you_win+=1 elif(ans == -1):  pc_win+=1 print "為了減少誤判,請盡可能將手占據盡可能大的框框"main()            
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