網上搜到一個Pygame寫的俄羅斯方塊（tetris），大部分看懂的前提下增加了注釋，Fedora19下運行OK的

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#coding:utf8#! /usr/bin/env python# 注釋說明：shape表示一個俄羅斯方塊形狀 cell表示一個小方塊import sysfrom random import choiceimport pygamefrom pygame.locals import *from block import O, I, S, Z, L, J, TCOLS = 16ROWS = 20CELLS = COLS * ROWSCELLPX = 32 # 每個cell的像素寬度POS_FIRST_APPEAR = COLS / 2SCREEN_SIZE = (COLS * CELLPX, ROWS * CELLPX)COLOR_BG = (0, 0, 0)def draw(grid, pos=None):  # grid是一個list，要么值為None，要么值為'Block'  # 非空值在eval（）的作用下，用于配置顏色  if pos: # 6x5    s = pos - 3 - 2 * COLS # upper left position    for p in range(0, COLS):      q = s + p * COLS      for i in range(q, q + 6):        if 0 <= i < CELLS:          # 0 <=i < CELLS:表示i這個cell在board內部。          c = eval(grid[i] + ".color") if grid[i] else COLOR_BG          # 執行著色。shape的cell涂對應的class設定好的顏色，否則涂黑（背景色）          a = i % COLS * CELLPX          b = i / COLS * CELLPX          screen.fill(c, (a, b, CELLPX, CELLPX))  else: # all    screen.fill(COLOR_BG)    for i, occupied in enumerate(grid):      if occupied:        c = eval(grid[i] + ".color") # 獲取方塊對應的顏色        a = i % COLS * CELLPX # 橫向長度        b = i / COLS * CELLPX # 縱向長度        screen.fill(c, (a, b, CELLPX, CELLPX))        # fill:為cell上色, 第二個參數表示rect  pygame.display.flip()  # 刷新屏幕def phi(grid1, grid2, pos): # 4x4# 兩個grid之4*4區域內是否會相撞（沖突）  s = pos - 2 - 1 * COLS # upper left position  for p in range(0, 4):    q = s + p * COLS    for i in range(q, q + 4):      try:        if grid1[i] and grid2[i]:          return False      except:        pass  return Truedef merge(grid1, grid2):  # 合并兩個grid  grid = grid1[:]  for i, c in enumerate(grid2):    if c:      grid[i] = c  return griddef complete(grid):  # 減去滿行  n = 0  for i in range(0, CELLS, COLS):    # 步長為一行。    if not None in grid[i:i + COLS]:    #這一句很容易理解錯誤。    #實際含義是：如果grid[i:i + COLS]都不是None,那么執行下面的語句      grid = [None] * COLS + grid[:i] + grid[i + COLS:]      n += 1  return grid, n#n表示減去的行數，用作統計分數pygame.init()pygame.event.set_blocked(None)pygame.event.set_allowed((KEYDOWN, QUIT))pygame.key.set_repeat(75, 0)pygame.display.set_caption('Tetris')screen = pygame.display.set_mode(SCREEN_SIZE)pygame.display.update()grid = [None] * CELLSspeed = 500screen.fill(COLOR_BG)while True: # spawn a block  block = choice([O, I, S, Z, L, J, T])()  pos = POS_FIRST_APPEAR  if not phi(grid, block.grid(pos), pos): break # you lose  pygame.time.set_timer(KEYDOWN, speed)  # repeatedly create an event on the event queue  # speed是時間間隔。。。speed越小，方塊下落的速度越快。。。speed應該換為其他名字  while True: # move the block    draw(merge(grid, block.grid(pos)), pos)    event = pygame.event.wait()    if event.type == QUIT: sys.exit()    try:      aim = {        K_UNKNOWN: pos+COLS,        K_UP: pos,        K_DOWN: pos+COLS,        K_LEFT: pos-1,        K_RIGHT: pos+1,      }[event.key]    except KeyError:      continue    if event.key == K_UP:      # 變形      block.rotate()    elif event.key in (K_LEFT, K_RIGHT) and pos / COLS != aim / COLS:      # pos/COLS表示當前位置所在行      # aim/COLS表示目標位置所在行      # 此判斷表示，當shape在左邊界時，不允許再向左移動（越界。。）,在最右邊時向右也禁止      continue    grid_aim = block.grid(aim)    if grid_aim and phi(grid, grid_aim, aim):      pos = aim    else:      if event.key == K_UP:        block.rotate(times=3)      elif not event.key in (K_LEFT, K_RIGHT):        break  grid = merge(grid, block.grid(pos))  grid, n = complete(grid)  if n:    draw(grid)    speed -= 5 * n    if speed < 75: speed = 75