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C#數(shù)據(jù)結(jié)構(gòu)之循環(huán)鏈表的實(shí)例代碼

2020-01-24 03:31:55
字體:
供稿:網(wǎng)友

復(fù)制代碼 代碼如下:

    public class Node
    {
        public object Element;
        public Node Link;

        public Node()
        {
            Element = null;
            Link = null;
        }

        public Node(object theElement)
        {
            Element = theElement;
            Link = null;
        }
    }

復(fù)制代碼 代碼如下:

public class LinkedList
    {
        //頭結(jié)點(diǎn)
        protected Node Header;

        private int count;

        public LinkedList()
        {
            count = 0;
            Header = new Node("header");
            Header.Link = Header;
        }

        public bool IsEmpty()
        {
            return (Header.Link == null);
        }

        public void MakeEmpty()
        {
            Header.Link = null;
        }

        public void PrintList()
        {
            Node current = new Node();
            current = Header;
            while (current.Link.Element.ToString() != "header")
            {
                Console.WriteLine(current.Link.Element);
                current = current.Link;
            }
        }

        private Node FindPrevious(object n)
        {
            Node current = Header;
            while (!(current.Link == null) && current.Link.Element != n)
            {
                current = current.Link;
            }
            return current;
        }

        private Node Find(object item)
        {
            Node current = new Node();
            current = Header.Link;
            while (current.Element != item)
            {
                current = current.Link;
            }
            return current;
        }

        public void Insert(object newItem, object after)
        {
            Node current = new Node();
            Node newNode = new Node(newItem);
            current = Find(after);
            newNode.Link = current.Link;
            current.Link = newNode;
            count++;
        }

        public void Remove(object n)
        {
            Node p = FindPrevious(n);
            if (!(p.Link == null))
            {
                p.Link = p.Link.Link;
                count--;
            }
        }

        public void InsertFirst(object n)
        {
            Node current = new Node(n);
            current.Link = Header;
            Header.Link = current;
            count++;
        }

        public Node Move(int n)
        {
            Node current = Header.Link;
            Node tmp;
            for (int i = 0; i <= n; i++)
            {
                current = current.Link;
            }
            if (current.Element.ToString() == "header")
            {
                current = current.Link;
            }
            tmp = current;
            return tmp;
        }

        public Node GetFirst()
        {
            return Header;
        }
    }

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