描述 Given a string s consists of upper/lower-case alphabets and empty space characters ’ ‘, return the length of last Word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example, Given s = “Hello World”, return 5.
分析 字符串序列中最后一個word的長度。 順序掃描，記錄每個word的長度，返回即可。
代碼
class Solution {public: int lengthOfLastWord(string s) { int len = 0; for (size_t i = 0; i < s.size();) { if (s[i++] != ' ') ++len; else if (i < s.size() && s[i] != ' ') len = 0; } return len; }};新聞熱點
疑難解答
