国产探花免费观看_亚洲丰满少妇自慰呻吟_97日韩有码在线_资源在线日韩欧美_一区二区精品毛片,辰东完美世界有声小说,欢乐颂第一季,yy玄幻小说排行榜完本

首頁 > 學院 > 開發設計 > 正文

506. Relative Ranks

2019-11-10 17:59:40
字體:
來源:轉載
供稿:網友

Given scores of N athletes, find their relative ranks and the people with the top three highest scores, who will be awarded medals: "Gold Medal", "Silver Medal" and "Bronze Medal".

Example 1:

Input: [5, 4, 3, 2, 1]Output: ["Gold Medal", "Silver Medal", "Bronze Medal", "4", "5"]Explanation: The first three athletes got the top three highest scores, so they got "Gold Medal", "Silver Medal" and "Bronze Medal". For the left two athletes, you just need to output their relative ranks according to their scores.

Note:

N is a positive integer and won't exceed 10,000.All the scores of athletes are guaranteed to be unique.

Subscribe to see which companies asked this question.

給每一個數一個排名,前三名是金銀銅。這是排序的問題。將原序列的每個數的鍵值和值組成pair,然后按值從大到小排序。最后按順序給排名就行了。

代碼:

class Solution{public:	vector<string> findRelativeRanks(vector<int>& nums)	{		vector<pair<int, int> > vec;		vector<string> res(nums.size());		string ranks[3] = {"Gold Medal", "Silver Medal", "Bronze Medal"};		for(int i = 0; i < nums.size(); ++i) 			vec.push_back(pair<int, int>(i, nums[i]));		auto cmp = [](const pair<int, int>& p1, const pair<int, int>& p2) { return p1.second > p2.second; };		sort(vec.begin(), vec.end(), cmp);		for(int i = 0; i < nums.size(); ++i)		{			if(i < 3) res[vec[i].first] = ranks[i];			else res[vec[i].first] = to_string(i+1);		}		return res;	}};


發表評論 共有條評論
用戶名: 密碼:
驗證碼: 匿名發表
主站蜘蛛池模板: 江安县| 荥阳市| 久治县| 广安市| 财经| 观塘区| 崇信县| 德化县| 夏河县| 泗水县| 循化| 平湖市| 东乌珠穆沁旗| 佛学| 冷水江市| 台北市| 保山市| 正镶白旗| 定州市| 奉新县| 抚州市| 南陵县| 泗洪县| 桓仁| 上高县| 茌平县| 玉林市| 石河子市| 博兴县| 萨嘎县| 集贤县| 九台市| 山东| 比如县| 理塘县| 临沭县| 年辖:市辖区| 玛曲县| 忻州市| 黎川县| 叙永县|