由于之前的業(yè)務(wù),造成數(shù)據(jù)庫(kù)上產(chǎn)生了臟數(shù)據(jù),寫個(gè)腳本刪除重復(fù)的數(shù)據(jù)。由于是開發(fā)測(cè)試環(huán)境,所以選擇任意刪除相同uid中的一條。由于每次執(zhí)行只刪除重復(fù)數(shù)據(jù)的一條,需要重復(fù)執(zhí)行,如果本輪沒有數(shù)據(jù)被刪就OK
#!/bin/sh# delete all company's duplicate uidMYSQL_BIN_PATH=/data/mysql/server/mysql_3306/binMYSQL_SOCK_PATH=/data/mysql/server/mysql_3306/tmpDBUSER=dbuserDBPWD=userpwdDBHOSTNAME=192.168.1.105PORT=3306# get all company_idfor company_id in `${MYSQL_BIN_PATH}/mysql -u${DBUSER} -p${DBPWD} -h ${DBHOSTNAME} -P ${PORT} --socket=${MYSQL_SOCK_PATH}/mysql.sock -e " SELECT company_id FROM company.companypage;"`do if [ $company_id != "company_id" ] ; then# if [ $company_id -eq 2733 ] ; then suffix=`expr ${company_id} % 100` for user_id in `${MYSQL_BIN_PATH}/mysql -u${DBUSER} -p${DBPWD} -h ${DBHOSTNAME} -P ${PORT} --socket=${MYSQL_SOCK_PATH}/mysql.sock -e " SELECT user_id FROM company.company_candidate_${suffix} WHERE company_id=${company_id} AND user_id>0 GROUP BY company_id, user_id HAVING COUNT(user_id) > 1;"` do if [ $user_id != "user_id" ] ; then ${MYSQL_BIN_PATH}/mysql -u${DBUSER} -p${DBPWD} -h ${DBHOSTNAME} -P ${PORT} --socket=${MYSQL_SOCK_PATH}/mysql.sock -e " DELETE FROM company.company_candidate_${suffix} WHERE company_id=${company_id} and user_id=${user_id} limit 1;" echo "delete from company_candidate_${suffix} where company_id=${company_id} and user_id=${user_id} limit 1" fi done# fi fidoneexit 0總結(jié)
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