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詳解Android獲取設備唯一ID的幾種方式

2019-10-22 18:35:27
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來源:轉載
供稿:網友

先來看看幾種比較單一的方式:

IMEI

方式:TelephonyManager.getDeviceId():

問題

  1. 范圍:只能支持擁有通話功能的設備,對于平板不可以。
  2. 持久性:返廠,數據擦除的時候不徹底,保留了原來的標識。
  3. 權限:需要權限:Android.permission.READ_PHONE_STATE
  4. bug: 有些廠家的實現有bug,返回一些不可用的數據

 Mac地址

ACCESS_WIFI_STATE權限

有些設備沒有WiFi,或者藍牙,就不可以,如果WiFi沒有打開,硬件也不會返回Mac地址,不建議使用

ANDROID_ID
2.2(Froyo,8)版本系統會不可信,來自主要生產廠商的主流手機,至少有一個普遍發現的bug,這些有問題的手機相同的ANDROID_ID: 9774d56d682e549c

但是如果返廠的手機,或者被root的手機,可能會變

Serial Number

從Android 2.3 (“Gingerbread”)開始可用,可以通過android.os.Build.SERIAL獲取,對于沒有通話功能的設備,它會返回一個唯一的device ID,

以下幾個是stackoverflow上評論較多的幾個,沒貼完,還有其他,綜合的,用到以上的部分方式:

地址:http://stackoverflow.com/questions/2785485/is-there-a-unique-android-device-id

有興趣的朋友可以再仔細看看

支持率比較高的(支持票數157):androidID --> 剔除2.2版本(API 8)中有問題的手機,使用UUID替代

import android.content.Context; import android.content.SharedPreferences; import android.provider.Settings.Secure; import android.telephony.TelephonyManager;  import java.io.UnsupportedEncodingException; import java.util.UUID;  public class DeviceUuidFactory {    protected static final String PREFS_FILE = "device_id.xml";   protected static final String PREFS_DEVICE_ID = "device_id";   protected static volatile UUID uuid;    public DeviceUuidFactory(Context context) {     if (uuid == null) {       synchronized (DeviceUuidFactory.class) {         if (uuid == null) {           final SharedPreferences prefs = context               .getSharedPreferences(PREFS_FILE, 0);           final String id = prefs.getString(PREFS_DEVICE_ID, null);           if (id != null) {             // Use the ids previously computed and stored in the             // prefs file             uuid = UUID.fromString(id);           } else {             final String androidId = Secure.getString(               context.getContentResolver(), Secure.ANDROID_ID);             // Use the Android ID unless it's broken, in which case             // fallback on deviceId,             // unless it's not available, then fallback on a random             // number which we store to a prefs file             try {               if (!"9774d56d682e549c".equals(androidId)) {                 uuid = UUID.nameUUIDFromBytes(androidId                     .getBytes("utf8"));               } else {                 final String deviceId = ((TelephonyManager)                      context.getSystemService(                       Context.TELEPHONY_SERVICE)                       .getDeviceId();                 uuid = deviceId != null ? UUID                     .nameUUIDFromBytes(deviceId                         .getBytes("utf8")) : UUID                     .randomUUID();               }             } catch (UnsupportedEncodingException e) {               throw new RuntimeException(e);             }             // Write the value out to the prefs file             prefs.edit()                 .putString(PREFS_DEVICE_ID, uuid.toString())                 .commit();           }         }       }     }   }    /**    * Returns a unique UUID for the current android device. As with all UUIDs,    * this unique ID is "very highly likely" to be unique across all Android    * devices. Much more so than ANDROID_ID is.    *    * The UUID is generated by using ANDROID_ID as the base key if appropriate,    * falling back on TelephonyManager.getDeviceID() if ANDROID_ID is known to    * be incorrect, and finally falling back on a random UUID that's persisted    * to SharedPreferences if getDeviceID() does not return a usable value.    *    * In some rare circumstances, this ID may change. In particular, if the    * device is factory reset a new device ID may be generated. In addition, if    * a user upgrades their phone from certain buggy implementations of Android    * 2.2 to a newer, non-buggy version of Android, the device ID may change.    * Or, if a user uninstalls your app on a device that has neither a proper    * Android ID nor a Device ID, this ID may change on reinstallation.    *    * Note that if the code falls back on using TelephonyManager.getDeviceId(),    * the resulting ID will NOT change after a factory reset. Something to be    * aware of.    *    * Works around a bug in Android 2.2 for many devices when using ANDROID_ID    * directly.    *    * @see http://code.google.com/p/android/issues/detail?id=10603    *    * @return a UUID that may be used to uniquely identify your device for most    *     purposes.    */   public UUID getDeviceUuid() {     return uuid;   } } 

根據版本進行判斷的方式:Serial序列號-->UUID (支持數31)

通過Serial 即可,在覆蓋率上,你已經成功的獲得了98.4%的用戶,剩下的1.6%的用戶系統是在9 以下的。

通過AndroidID獲取,前面已經說過,在8上,有些商家的手機會有一些bug,返回相同的AndroidID,如果Serial和AndroidID都不行

/**  * Return pseudo unique ID  * @return ID  */ public static String getUniquePsuedoID() {   // If all else fails, if the user does have lower than API 9 (lower   // than Gingerbread), has reset their phone or 'Secure.ANDROID_ID'   // returns 'null', then simply the ID returned will be solely based   // off their Android device information. This is where the collisions   // can happen.   // Thanks http://www.pocketmagic.net/?p=1662!   // Try not to use DISPLAY, HOST or ID - these items could change.   // If there are collisions, there will be overlapping data   String m_szDevIDShort = "35" + (Build.BOARD.length() % 10) + (Build.BRAND.length() % 10) + (Build.CPU_ABI.length() % 10) + (Build.DEVICE.length() % 10) + (Build.MANUFACTURER.length() % 10) + (Build.MODEL.length() % 10) + (Build.PRODUCT.length() % 10);    // Thanks to @Roman SL!   // http://stackoverflow.com/a/4789483/950427   // Only devices with API >= 9 have android.os.Build.SERIAL   // http://developer.android.com/reference/android/os/Build.html#SERIAL   // If a user upgrades software or roots their phone, there will be a duplicate entry   String serial = null;   try   {     serial = android.os.Build.class.getField("SERIAL").get(null).toString();      // Go ahead and return the serial for api => 9     return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString();   }   catch (Exception e)   {     // String needs to be initialized     serial = "serial"; // some value   }    // Thanks @Joe!   // http://stackoverflow.com/a/2853253/950427   // Finally, combine the values we have found by using the UUID class to create a unique identifier   return new UUID(m_szDevIDShort.hashCode(), serial.hashCode()).toString(); } 

不用READ_PHONE_STATE權限直接獲取ROM信息的方式:(支持率較低 16)

String m_szDevIDShort = "35" + //we make this look like a valid IMEI       Build.BOARD.length()%10+ Build.BRAND.length()%10 +       Build.CPU_ABI.length()%10 + Build.DEVICE.length()%10 +       Build.DISPLAY.length()%10 + Build.HOST.length()%10 +       Build.ID.length()%10 + Build.MANUFACTURER.length()%10 +       Build.MODEL.length()%10 + Build.PRODUCT.length()%10 +       Build.TAGS.length()%10 + Build.TYPE.length()%10 +       Build.USER.length()%10 ; //13 digits 

最后貼上自己在項目中用的:

public static String getDeviceId(Context context) {     String deviceId = "";     if (deviceId != null && !"".equals(deviceId)) {      return deviceId;    }     if (deviceId == null || "".equals(deviceId)) {       try {         deviceId = getLocalMac(context).replace(":", "");       } catch (Exception e) {         e.printStackTrace();       }     }     if (deviceId == null || "".equals(deviceId)) {       try {         deviceId = getAndroidId(context);       } catch (Exception e) {         e.printStackTrace();       }     }     if (deviceId == null || "".equals(deviceId)) {              if (deviceId == null || "".equals(deviceId)) {         UUID uuid = UUID.randomUUID();         deviceId = uuid.toString().replace("-", "");         writeDeviceID(deviceId);       }     }     return deviceId;   } 
// IMEI碼   private static String getIMIEStatus(Context context) {     TelephonyManager tm = (TelephonyManager) context         .getSystemService(Context.TELEPHONY_SERVICE);     String deviceId = tm.getDeviceId();     return deviceId;   }    // Mac地址   private static String getLocalMac(Context context) {     WifiManager wifi = (WifiManager) context         .getSystemService(Context.WIFI_SERVICE);     WifiInfo info = wifi.getConnectionInfo();     return info.getMacAddress();   }    // Android Id   private static String getAndroidId(Context context) {     String androidId = Settings.Secure.getString(         context.getContentResolver(), Settings.Secure.ANDROID_ID);     return androidId;   }    public static void saveDeviceID(String str) {     try {       FileOutputStream fos = new FileOutputStream(file);       Writer out = new OutputStreamWriter(fos, "UTF-8");       out.write(str);       out.close();     } catch (IOException e) {       e.printStackTrace();     }   }    public static String readDeviceID() {     StringBuffer buffer = new StringBuffer();     try {       FileInputStream fis = new FileInputStream(file);       InputStreamReader isr = new InputStreamReader(fis, "UTF-8");       Reader in = new BufferedReader(isr);       int i;       while ((i = in.read()) > -1) {         buffer.append((char) i);       }       in.close();       return buffer.toString();     } catch (IOException e) {       e.printStackTrace();       return null;     }   } 

對于獲取設備唯一ID并沒有絕對的方案,這一點在android的官方博客中也提到了,不過以上幾種方案,應該可以滿足平時的需求,大家可以選擇其中自己認為比較好的,用于自己的項目中。

以上就是本文的全部內容,希望對大家的學習有所幫助,也希望大家多多支持VEVB武林網。


注:相關教程知識閱讀請移步到Android開發頻道。
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