IOS開發(fā)之判斷兩個(gè)數(shù)組中數(shù)據(jù)是否相同實(shí)例詳解
前言:
工作中遇到的問題,這里記錄下,也許能幫助到大家
實(shí)例代碼:
NSArray *array1 = [NSArray arrayWithObjects:@"a", @"b", @"c", nil nil]; NSArray *array2 = [NSArray arrayWithObjects:@"b", @"a", @"c", nil nil]; bool bol = false; //創(chuàng)建倆新的數(shù)組 NSMutableArray *oldArr = [NSMutableArray arrayWithArray:array1]; NSMutableArray *newArr = [NSMutableArray arrayWithArray:array2]; //對(duì)數(shù)組1排序。 [oldArr sortUsingComparator:^NSComparisonResult(id obj1, id obj2){ return obj1 > obj2; }]; ////上個(gè)排序好像不起作用,應(yīng)采用下面這個(gè)[oldArr sortUsingComparator:^NSComparisonResult(id obj1, id obj2){return [obj1 localizedStandardCompare: obj2];}]; //對(duì)數(shù)組2排序。 [newArr sortUsingComparator:^NSComparisonResult(id obj1, id obj2){ return obj1 > obj2; }]; ////上個(gè)排序好像不起作用,應(yīng)采用下面這個(gè)[newArr sortUsingComparator:^NSComparisonResult(id obj1, id obj2){return [obj1 localizedStandardCompare: obj2];}]; if (newArr.count == oldArr.count) { bol = true; for (int16_t i = 0; i < oldArr.count; i++) { id c1 = [oldArr objectAtIndex:i]; id newc = [newArr objectAtIndex:i]; if (![newc isEqualToString:c1];) { bol = false; break; } } } if (bol) { NSLog(@"兩個(gè)數(shù)組的內(nèi)容相同!"); } else { NSLog(@"兩個(gè)數(shù)組的內(nèi)容不相同!"); } 感謝閱讀,希望能幫助到大家,謝謝大家對(duì)本站的支持!
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