php計算兩個坐標（經度，緯度）之間距離的方法

2024-09-04 11:49:29

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來源：轉載

供稿：網友

例子一:

function distance($lat1, $lng1, $lat2, $lng2, $miles = true){

$pi80 = M_PI / 180;

$lat1 *= $pi80;

$lng1 *= $pi80;

$lat2 *= $pi80;

$lng2 *= $pi80;

$r = 6372.797;

$dlat = $lat2 - $lat1;

$dlng = $lng2 - $lng1;

$a = sin($dlat/2)*sin($dlat/2)+cos($lat1)*cos($lat2)*sin($dlng/2)*sin($dlng/2);

$c = 2 * atan2(sqrt($a), sqrt(1 - $a));

$km = $r * $c;

return ($miles ? ($km * 0.621371192) : $km);

}

例子二:

/**

* 計算兩個坐標之間的距離(米)

* @param float $fP1Lat 起點(緯度)

* @param float $fP1Lon 起點(經度)

* @param float $fP2Lat 終點(緯度)

* @param float $fP2Lon 終點(經度)

* @return int

*/

function distanceBetween($fP1Lat, $fP1Lon, $fP2Lat, $fP2Lon){

    $fEARTH_RADIUS = 6378137;

    //角度換算成弧度

    $fRadLon1 = deg2rad($fP1Lon);

    $fRadLon2 = deg2rad($fP2Lon);

    $fRadLat1 = deg2rad($fP1Lat);

    $fRadLat2 = deg2rad($fP2Lat);

    //計算經緯度的差值

    $fD1 = abs($fRadLat1 - $fRadLat2);

    $fD2 = abs($fRadLon1 - $fRadLon2);

    //距離計算

    $fP = pow(sin($fD1/2), 2) +

          cos($fRadLat1) * cos($fRadLat2) * pow(sin($fD2/2), 2);

    return intval($fEARTH_RADIUS * 2 * asin(sqrt($fP)) + 0.5);

}

/**

* 百度坐標系轉換成標準GPS坐系

* @param float $lnglat 坐標(如:106.426, 29.553404)

* @return string 轉換后的標準GPS值:

*/

function BD09LLtoWGS84($fLng, $fLat){ // 經度,緯度

    $lnglat = explode(',', $lnglat);

    list($x,$y) = $lnglat;

    $Baidu_Server = "http://api.map.baidu.com/ag/coord/convert?from=0&to=4&x={$x}&y={$y}";

    $result = @file_get_contents($Baidu_Server);

    $json = json_decode($result);

    if($json->error == 0){

        $bx = base64_decode($json->x);

        $by = base64_decode($json->y);

        $GPS_x = 2 * $x - $bx;

        $GPS_y = 2 * $y - $by;

        return $GPS_x.','.$GPS_y;//經度,緯度

    }else

        return $lnglat;

}