FROM (SELECT NUM, UPD_DATE, INBOUND_QTY, STOCK_ONHAND
FROM TABLE2
WHERE TO_CHAR(UPD_DATE,'YYYY/MM') = TO_CHAR(SYSDATE, 'YYYY/MM')) X,
(SELECT NUM, UPD_DATE, STOCK_ONHAND
FROM TABLE2
WHERE TO_CHAR(UPD_DATE,'YYYY/MM') =
TO_CHAR(TO_DATE(TO_CHAR(SYSDATE, 'YYYY/MM') || '/01','YYYY/MM/DD') - 1, 'YYYY/MM') ) Y,
WHERE X.NUM = Y.NUM （+）
AND X.INBOUND_QTY + NVL(Y.STOCK_ONHAND,0) <> X.STOCK_ONHAND ) B
WHERE A.NUM = B.NUM
說明：-- select * from studentinfo where not exists(select * from student where studentinfo.id=student.id) and 系名稱='"&strdepartmentname&"' and 專業名稱 ='"&strprofessionname&"' order by 性別,生源地,高考總成績
從數據庫中去一年的各單位電話費統計(電話費定額賀電化肥清單兩個表來源）
SELECT a.userper, a.tel, a.standfee, TO_CHAR(a.telfeedate, 'yyyy') AS telyear,
SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '01', a.factration)) AS JAN,
SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '02', a.factration)) AS FRI,
SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '03', a.factration)) AS MAR,
SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '04', a.factration)) AS APR,
SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '05', a.factration)) AS MAY,
SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '06', a.factration)) AS JUE,
SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '07', a.factration)) AS JUL,
SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '08', a.factration)) AS AGU,
SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '09', a.factration)) AS SEP,
SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '10', a.factration)) AS OCT,
SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '11', a.factration)) AS NOV,
SUM(decode(TO_CHAR(a.telfeedate, 'mm'), '12', a.factration)) AS DEC
FROM (SELECT a.userper, a.tel, a.standfee, b.telfeedate, b.factration
FROM TELFEESTAND a, TELFEE b
WHERE a.tel = b.telfax) a
GROUP BY a.userper, a.tel, a.standfee, TO_CHAR(a.telfeedate, 'yyyy')
說明：四表聯查問題 select * from a left inner join b on a.a=b.b right inner join c on a.a=c.c inner join d on a.a=d.d where .....
說明：得到表中最小的未使用的ID號
SELECT (CASE WHEN EXISTS(SELECT * FROM Handle b WHERE b.HandleID = 1) THEN MIN(HandleID) + 1 ELSE 1 END) as HandleID FROM Handle WHERE NOT HandleID IN (SELECT a.HandleID - 1 FROM Handle a)
一個SQL語句的問題:行列轉換 select * from v_temp 上面的視圖結果如下: user_name role_name ------------------------- 系統管理員 管理員 feng 管理員 feng 一般用戶 test 一般用戶 想把結果變成這樣: user_name role_name --------------------------- 系統管理員 管理員 feng 管理員,一般用戶 test 一般用戶 =================== create table a_test(name varchar(20),role2 varchar(20)) insert into a_test values('李','管理員') insert into a_test values('張','管理員') insert into a_test values('張','一般用戶') insert into a_test values('常','一般用戶')
create function join_str(@content varchar(100)) returns varchar(2000) as begin declare @str varchar(2000) set @str='' select @str=@str+','+rtrim(role2) from a_test where [name]=@content select @str=right(@str,len(@str)-1) return @str end go
--調用： select [name],dbo.join_str([name]) role2 from a_test group by [name]
--select distinct name,dbo.uf_test(name) from a_test
快速比較結構相同的兩表 結構相同的兩表，一表有記錄3萬條左右，一表有記錄2萬條左右，我怎樣快速查找兩表的不同記錄？ ============================ 給你一個測試方法，從northwind中的orders表取數據。 select * into n1 from orders select * into n2 from orders
select * from n1 select * from n2
--添加主鍵，然后修改n1中若干字段的若干條 alter table n1 add constraint pk_n1_id primary key (OrderID) alter table n2 add constraint pk_n2_id primary key (OrderID)
select OrderID from (select * from n1 union select * from n2) a group by OrderID having count(*) > 1
應該可以，而且將不同的記錄的ID顯示出來。 下面的適用于雙方記錄一樣的情況，
select * from n1 where orderid in (select OrderID from (select * from n1 union select * from n2) a group by OrderID having count(*) > 1) 至于雙方互不存在的記錄是比較好處理的 --刪除n1,n2中若干條記錄 delete from n1 where orderID in ('10728','10730') delete from n2 where orderID in ('11000','11001')
--************************************************************* -- 雙方都有該記錄卻不完全相同 select * from n1 where orderid in(select OrderID from (select * from n1 union select * from n2) a group by OrderID having count(*) > 1) union --n2中存在但在n1中不存的在10728,10730 select * from n1 where OrderID not in (select OrderID from n2) union --n1中存在但在n2中不存的在11000,11001 select * from n2 where OrderID not in (select OrderID from n1)
四種方法取表里n到m條紀錄：
1. select top m * into 臨時表(或表變量) from tablename order by columnname -- 將top m筆插入 set rowcount n select * from 表變量 order by columnname desc
2. select top n * from (select top m * from tablename order by columnname) a order by columnname desc
3.如果tablename里沒有其他identity列，那么： select identity(int) id0,* into #temp from tablename
取n到m條的語句為： select * from #temp where id0 >=n and id0 <= m
如果你在執行select identity(int) id0,* into #temp from tablename這條語句的時候報錯,那是因為 你的DB中間的select into/bulkcopy屬性沒有打開要先執行： exec sp_dboption 你的DB名字,'select into/bulkcopy',true
4.如果表里有identity屬性，那么簡單： select * from tablename where identitycol between n and m
insert into a_dist values(1,'abc') insert into a_dist values(1,'abc') insert into a_dist values(1,'abc') insert into a_dist values(1,'abc')
exec up_distinct 'a_dist','id'
select * from a_dist
create procedure up_distinct(@t_name varchar(30),@f_key varchar(30)) --f_key表示是分組字段﹐即主鍵字段 as begin declare @max integer,@id varchar(30) ,@sql varchar(7999) ,@type integer select @sql = 'declare cur_rows cursor for select '+@f_key+' ,count(*) from ' +@t_name +' group by ' +@f_key +' having count(*) > 1' exec(@sql) open cur_rows fetch cur_rows into @id,@max while @@fetch_status=0 begin select @max = @max -1 set rowcount @max select @type = xtype from syscolumns where id=object_id(@t_name) and name=@f_key if @type=56 select @sql = 'delete from '+@t_name+' where ' + @f_key+' = '+ @id if @type=167 select @sql = 'delete from '+@t_name+' where ' + @f_key+' = '+''''+ @id +'''' exec(@sql) fetch cur_rows into @id,@max end close cur_rows deallocate cur_rows set rowcount 0 end
select * from systypes select * from syscolumns where id = object_id('a_dist')
insert into hard values ('A','1',3) insert into hard values ('A','2',4) insert into hard values ('A','4',2) insert into hard values ('A','6',9) insert into hard values ('B','1',4) insert into hard values ('B','2',5) insert into hard values ('B','3',6) insert into hard values ('C','3',4) insert into hard values ('C','6',7) insert into hard values ('C','2',3)
要求查詢出來的結果如下：
qu co je ----------- ----------- ----- A 6 9 A 2 4 B 3 6 B 2 5 C 6 7 C 3 4
就是要按qu分組，每組中取je最大的前2位！！ 而且只能用一句sql語句！！！ select * from hard a where je in (select top 2 je from hard b where a.qu=b.qu order by je)
