1、查找表中多余的重復(fù)記錄，重復(fù)記錄是根據(jù)單個(gè)字段（peopleId）來(lái)判斷

復(fù)制代碼 代碼如下:

select * from people
where peopleId in (select peopleId from people group by peopleId having count

(peopleId) > 1)

復(fù)制代碼 代碼如下:

delete from people
where peopleId in (select peopleId from people group by peopleId having count

(peopleId) > 1)
and rowid not in (select min(rowid) from people group by peopleId having count(peopleId

)>1)

復(fù)制代碼 代碼如下:

select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having

count(*) > 1)

復(fù)制代碼 代碼如下:

delete from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having

count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

復(fù)制代碼 代碼如下:

select * from vitae a
where (a.peopleId,a.seq) in (select peopleId,seq from vitae group by peopleId,seq having

count(*) > 1)
and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)

復(fù)制代碼 代碼如下:

Select Name,Count(*) From A Group By Name Having Count(*) > 1

復(fù)制代碼 代碼如下:

Select Name,sex,Count(*) From A Group By Name,sex Having Count(*) > 1

復(fù)制代碼 代碼如下:

declare @max integer,@id integer
declare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having

count(*) >； 1
open cur_rows
fetch cur_rows into @id,@max
while @@fetch_status=0
begin
select @max = @max -1
set rowcount @max
delete from 表名 where 主字段 = @id
fetch cur_rows into @id,@max
end
close cur_rows
set rowcount 0

　　有兩個(gè)意義上的重復(fù)記錄，一是完全重復(fù)的記錄，也即所有字段均重復(fù)的記錄，二是部分關(guān)鍵字段重

復(fù)的記錄，比如Name字段重復(fù)，而其他字段不一定重復(fù)或都重復(fù)可以忽略。

　　1、對(duì)于第一種重復(fù)，比較容易解決，使用

復(fù)制代碼 代碼如下:

select distinct * from tableName

　　如果該表需要?jiǎng)h除重復(fù)的記錄（重復(fù)記錄保留1條），可以按以下方法刪除

復(fù)制代碼 代碼如下:

select distinct * into #Tmp from tableName
drop table tableName
select * into tableName from #Tmp
drop table #Tmp

　　2、這類(lèi)重復(fù)問(wèn)題通常要求保留重復(fù)記錄中的第一條記錄，操作方法如下

　　假設(shè)有重復(fù)的字段為Name,Address，要求得到這兩個(gè)字段唯一的結(jié)果集

復(fù)制代碼 代碼如下:

select identity(int,1,1) as autoID, * into #Tmp from tableName
select min(autoID) as autoID into #Tmp2 from #Tmp group by Name,autoID
select * from #Tmp where autoID in(select autoID from #tmp2)

在select子句中省去此列）

(四)查詢(xún)重復(fù)

復(fù)制代碼 代碼如下:

select * from tablename where id in (
select id from tablename
group by id
having count(id) > 1
)