以下有兩個表，他們的結(jié)構(gòu)完全相同，請通過SQL找出值不同的列。
Student_1
Student_2
方法一 -- NOT EXISTS：
復制代碼 代碼如下:www.survivalescaperooms.com
SELECT *
FROM Student_1 S1
WHERE NOT EXISTS
(SELECT *
FROM Student_2 S2
WHERE S1.name = S2.name
AND S1.age = S2.age
AND S1.score = S2.score
)
UNION ALL
SELECT *
FROM STUDENT_2 S2
WHERE NOT EXISTS
(SELECT *
FROM STUDENT_1 S1
WHERE S1.name = S2.name
AND S1.age = S2.age
AND S1.score = S2.score
);
方法二 -- MINUS
復制代碼 代碼如下:www.survivalescaperooms.com
(SELECT * FROM Student_1
MINUS
SELECT * FROM Student_2)
UNION ALL
(SELECT * FROM Student_2
MINUS
SELECT * FROM Student_1)
方法三 -- HAVING GROUP BY
復制代碼 代碼如下:www.survivalescaperooms.com
SELECT DISTINCT name, age, score FROM (
SELECT * FROM Student_1
UNION ALL
SELECT * FROM Student_2
)GROUP BY name, age, score HAVING COUNT(*)=1 ;
