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用x$dual代替dual所得到的結果是什么

2024-07-21 02:34:35
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  connect / as sysdba
  create view dual2 
    as select dummy from x$dual
    where instance = USERENV('INSTANCE');
  grant select on dual2 to public;
  create public synonym dual2 for dual2;
   
  connect scott/tiger; 
   
  create table temp 
  ( sqlno number(3),
    b_a varchar2(2),
    stat number,
    value number
  );
   
  SQL> l
    1 declare
    2   v_dummy date;
    3   v_start number;
    4 begin
    5   insert into temp select 1,'b',statistic#,value from v$mystat;
    6   v_start := dbms_utility.get_time;
    7   for i in 1..2000 loop
    8     select sysdate into v_dummy from dual;
    9   end loop;
   10   dbms_output.put_line('1st stat used: '(dbms_utility.get_time - v_start)' seconds');
   11
   12   insert into temp select 1,'ab',statistic#,value from v$mystat;
   13   v_start := dbms_utility.get_time;
   14   for i in 1..2000 loop
   15     select sysdate into v_dummy from dual2;
   16   end loop;
   17   dbms_output.put_line('2st stat used: '(dbms_utility.get_time - v_start)' seconds');
   18   insert into temp select 2,'a',statistic#,value from v$mystat;
   19 end;
   20*
  SQL> /
  1st stat used: 57 seconds
  2st stat used: 45 seconds
   
  PL/SQL PRocedure sUCcessfully completed.
   
  SQL> l
    1 select (select name from v$statname where statistic# = t2.stat) name, t1.value value1, t2.value value2
    2 from
    3 (
    4 select 1,b.stat,b.value - a.value value
    5 from
    6 (select * from temp
    7  where sqlno=1
    8  and b_a = 'b') a,
    9 (select * from temp
   10  where sqlno=1
   11  and b_a = 'ab') b
   12 where b.stat = a.stat
   13 ) t1,
   14 (select 2,t3.stat,t4.value - t3.value value
   15 from
   16 (select * from temp
   17  where sqlno=1
   18  and b_a = 'ab') t3,
   19 (select * from temp
   20  where sqlno=2
   21  and b_a = 'a') t4
   22 where t4.stat = t3.stat
   23 ) t2
   24 where t1.stat = t2.stat
   25* and t1.value <>t2.value
  SQL> /
   
  NAME                     VALUE1   VALUE2
  ---------------------------------------- ---------- ----------
  session logical reads             10016     20
  enqueue releases                 1     2
  db block gets                 8011     15
  consistent gets                2005     5
  db block changes                 8     18
  free buffer requested               1     2
  calls to kcmgcs                  0     2
  calls to get snapshot scn: kcmgss       2004    2002
  redo entries                   5     11
  redo size                   5124    5928
  no work - consistent read gets         2002     2
  table scans (short tables)           2000     0
  table scan rows gotten             2000     0
  table scan blocks gotten            2000     0
  buffer is not pinned count           2004     4
   
  15 rows selected. right">(出處:清風軟件下載學院)

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