我的BSOOC里需要一個(gè)查詢表主鍵外鍵信息的SQL，昨晚研究到凌晨1點(diǎn)，終于能實(shí)現(xiàn)這個(gè)目標(biāo)：
Oracle:
select o.obj# as objectId, o.name AS tableName, oc.name AS constraintName,
       decode(c.type#, 1, 'C', 2, 'P', 3, 'U',
              4, 'R', 5, 'V', 6, 'O', 7,'C', '?') as constraintType,
       col.name AS columnName
     
from sys.con$ oc, sys.con$ rc,
     sys.obj$ ro,sys.obj$ o, sys.obj$ oi,
     sys.cdef$ c,
     sys.col$ col, sys.ccol$ cc, sys.attrcol$ ac
where oc.con# = c.con#
  and c.obj# = o.obj#
  and c.rcon# = rc.con#(+)
  and c.enabled = oi.obj#(+)
  and c.robj# = ro.obj#(+)
  and c.type# != 8
  and c.type# != 12       /* don't include log groups */
  and c.con# = cc.con#
  and cc.obj# = col.obj#
  and cc.intcol# = col.intcol#
  and cc.obj# = o.obj#
  and col.obj# = ac.obj#(+)
  and col.intcol# = ac.intcol#(+)
  and o.name = 'your table'
 
SQL Server:

SELECT sysobjects.id objectId,
OBJECT_NAME(sysobjects.parent_obj) tableName,
sysobjects.name constraintName,
sysobjects.xtype AS constraintType,
syscolumns.name AS columnName
FROM sysobjects INNER JOIN sysconstraints
ON sysobjects.xtype in('C', 'F', 'PK', 'UQ', 'D')
 AND sysobjects.id = sysconstraints.constid
LEFT OUTER JOIN syscolumns ON sysconstraints.id = syscolumns.id
WHERE OBJECT_NAME(sysobjects.parent_obj)='your table'
 
其它數(shù)據(jù)庫還沒時(shí)間去實(shí)現(xiàn).