本文實例講述了asp.net提取多層嵌套json數(shù)據(jù)的方法。,具體如下:
在.net 2.0中提取這樣的json:
代碼如下:{"name":"lily","age":23,"addr":{"city":guangzhou,"province":guangdong}}
引用命名空間:
using Newtonsoft.Json;using Newtonsoft.Json.Linq;
可以把上面的JSON看成一個對象.你只要寫對應的類即可
public class UserInfo{public string name;public int age;public address addr;}public class address{public string city;public string province;}然后在解析的地方這樣寫:
string jsonData="{/"name/":/"lily/",/"age/":23,/"addr/":{/"city/":guangzhou,/"province/":guangdong}}";UserInfo user=(UserInfo)JsonConvert.DeserializeObject(jsonData, typeof(UserInfo));得到City的值只要:user.addr.City;
這樣實現(xiàn)也行
JObject jsonObj = JObject.Parse(jsonData);string name=jsonObj ["name"].ToString();string age=jsonObj ["age"].ToString();string city=((JObject )jsonObj ["addr"])["city"].ToString();string province=((JObject )jsonObj ["addr"])["province"].ToString();
如何這個json是動態(tài)的呢?譬如讓你輸入一個json,如
代碼如下:{"name":"lily","age":23,"addr":{"city":guangzhou,"province":guangdong}};
然后讓你輸入一個對象,如city,然后系統(tǒng)會輸出guangzhou這個值,那這樣的話,json就是動態(tài)生成的了,我想了解有沒有讀取這樣的json的方法。(注意,json是多級嵌套的。)
就用遍歷
public string GetJsonValue(JEnumerable<JToken> jToken,string key){IEnumerator enumerator = jToken.GetEnumerator();while (enumerator.MoveNext()){JToken jc = (JToken)enumerator.Current;if (jc is JObject||((JProperty)jc).Value is JObject){return GetJsonValue(jc.Children(), key);}else{if (((JProperty)jc).Name == key){return ((JProperty)jc).Value.ToString();}}}return null;}在調(diào)用的時候:
string jsonData = "{/"name/":/"lily/",/"age/":23,/"addr/":{/"city/":/"guangzhou/",/"province/":/"guangdong/"}}";JObject jsonObj = JObject.Parse(jsonData);Response.Write(GetJsonValue(jsonObj.Children(), "province"));如果有多層嵌套的數(shù)組
string jsonData = "{/"addr/":[{/"city/":/"guangzhou/",/"province/":/"guangdong/"},{/"city/":/"guiyang/",/"province/":/"guizhou/"}]}";JObject jsonObj = JObject.Parse(jsonData);JArray jar = JArray.Parse(jsonObj["addr"].ToString());JObject j = JObject.Parse(jar[0].ToString());Response.Write(j["city"]);JSON轉(zhuǎn)XML:
代碼如下:string xmlstr=((XmlDocument)JsonConvert.DeserializeXmlNode(jsonData)).InnerXml.ToString();
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