php 用戶cookie登錄驗(yàn)證與mysql數(shù)據(jù)登錄驗(yàn)證的方法

2024-05-04 21:47:41

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供稿：網(wǎng)友

php用戶cookie登錄驗(yàn)證與mysql數(shù)據(jù)登錄驗(yàn)證的方法:

<?php

unset($username);

if ($_COOKIE['login']) {

    list($c_username,$cookie_hash) = split(',',$_COOKIE['login']);

    if (md5($c_username.$secret_word) == $cookie_hash) {

        $username = $c_username;

    } else {

        print "You have sent a bad cookie.";

    }

}

if ($username) {

    print "Welcome, $username.";

} else {

    print "Welcome, anonymous user.";

}

?>

看個(gè)完整的與數(shù)據(jù)庫(kù)連接登錄的代碼:

<html>

<head>

<title>Log-In Page</title>

</head>

<body>

Please enter your user details to log-in here...

<form action = "authenticate.php" method = "post">

Username:<br>

<input type = "text" name = "username">

<br><br>

Password:<br>

<input type = "text" name = "password">

<br><br>

<input type = "submit" value = "Log In">

</form>

</body>

</html>

File:authenticate.php

<?php

$username = $_POST['username'];

$password = $_POST['password'];

$self =     $_SERVER['PHP_SELF'];

$referer =  $_SERVER['HTTP_REFERER'];

if( ( !$username ) or ( !$password ) )

{ header( "Location:$referer" ); exit(); }

$conn=@mysql_connect( "localhost", "userName", "password" ) or die( "Could not connect" );

$rs = @mysql_select_db( "my_database", $conn ) or die( "Could not select database" );

$sql = "select * from users where user_name="$username" and password = password( "$password" )";

$rs = mysql_query( $sql, $conn ) or die( "Could not execute query" );

$num = mysql_numrows( $rs );

if( $num != 0 )

{

  $msg = "<h3>Welcome $username - your log-in succeeded!</h3>";

}

else

{

  header( "Location:$referer" ); exit();

}

?>

<html>

<head>

  <title>Log-In Authenticated</title>

  </head>

  <body>

   <?php echo( $msg ); ?>

  </body>

</html>