今天寫了一個(gè)webservice接口，返回類型是DataTable ,運(yùn)行的時(shí)候報(bào)以下錯(cuò)誤：

System.InvalidOperationException: 生成 xml 文檔時(shí)出錯(cuò)。 --->

System.InvalidOperationException: 無法序列化 DataTable。未設(shè)置 DataTable 名稱。在 System.Data.DataTable.WriteXmlSchema(XmlWriter writer, Boolean writeHierarchy)在 System.Data.DataTable.System.Xml.Serialization.IXmlSerializable.WriteXml(XmlWriter writer)在 System.Xml.Serialization.XmlSerializationWriter.WriteSerializable(IXmlSerializable serializable, String name, String ns, Boolean isNullable, Boolean wrapped)在 Microsoft.Xml.Serialization.GeneratedAssembly.XmlSerializationWriter1.Write2_DataTable(Object o)在 Microsoft.Xml.Serialization.GeneratedAssembly.DataTableSerializer.Serialize(Object objectToSerialize, XmlSerializationWriter writer)在 System.Xml.Serialization.XmlSerializer.Serialize(XmlWriter xmlWriter, Object o, XmlSerializerNamespaces namespaces, String encodingStyle, String id)--- 內(nèi)部異常堆棧跟蹤的結(jié)尾 ---在 System.Xml.Serialization.XmlSerializer.Serialize(XmlWriter xmlWriter, Object o, XmlSerializerNamespaces namespaces, String encodingStyle, String id)在 System.Xml.Serialization.XmlSerializer.Serialize(TextWriter textWriter, Object o, XmlSerializerNamespaces namespaces)在 System.Xml.Serialization.XmlSerializer.Serialize(TextWriter textWriter, Object o)在 System.Web.Services.PRotocols.XmlReturnWriter.Write(HttpResponse response, Stream outputStream, Object returnValue)在 System.Web.Services.Protocols.HttpServerProtocol.WriteReturns(Object[] returnValues, Stream outputStream)在 System.Web.Services.Protocols.WebServiceHandler.WriteReturns(Object[] returnValues)在 System.Web.Services.Protocols.WebServiceHandler.Invoke()

解決方法：

給定義的Datatable命名。代碼：

DataTable table= new DataTable();

table.TableName = "tmp";