本文實例為大家分享了C++計算每個字符出現的次數的實現代碼，供大家參考，具體內容如下
#include <iostream>//#include <cstdlib>#include <ctime>using namespace std; const int NUMBER_OF_LETTERS = 26;const int NUMBER_OF_RANDOM_LETTERS = 100;void createArray(char []);void displayArray(const char []);void countLetters(const char [], int []);void displayCounts(const int []); int main(){ char chars[NUMBER_OF_RANDOM_LETTERS]; createArray(chars); cout << "The lowercase letters are:" << endl; displayArray(chars); int counts[NUMBER_OF_LETTERS]; countLetters(chars, counts); cout << "/nThe occurrences of each letter are:" << endl; displayCounts(counts); return 0;} void createArray(char chars[]){ srand((unsigned int)time(0)); for (int i = 0; i < NUMBER_OF_RANDOM_LETTERS; i++) { chars[i] = static_cast<char>('a' + rand() % ('z' - 'a' + 1)); }} void displayArray(const char chars[]){ for (int i = 0; i < NUMBER_OF_RANDOM_LETTERS; i++) { if ((i + 1) % 20 == 0) cout << chars[i] << " " << endl; else cout << chars[i] << " "; }} void countLetters(const char chars[], int counts[]){ for (int i = 0; i < NUMBER_OF_LETTERS; i++) counts[i] = 0; for (int i = 0; i < NUMBER_OF_RANDOM_LETTERS; i++) counts[chars[i] - 'a']++; //經典} void displayCounts(const int counts[]){ for (int i = 0; i < NUMBER_OF_LETTERS; i++) { if ((i + 1) % 10 == 0) cout << counts[i] << " " << static_cast<char>(i + 'a') << endl; else cout << counts[i] << " " << static_cast<char>(i + 'a') << " "; } cout << endl;} 以上就是本文的全部內容，希望對大家的學習有所幫助。
