//設置條件        NSPredicate *predicate=[NSPredicate predicateWithFormat:@"age<5"];        //與        NSPredicate *predicate1=[NSPredicate predicateWithFormat:@"age<9&&age>5"];        //或        NSPredicate *predicate2=[NSPredicate predicateWithFormat:@"age<3||age>5"];        //占位符傳參        NSPredicate *predicate3=[NSPredicate predicateWithFormat:@"age=%d",3];        //多條件        NSArray *arrayname=@[@"jack1",@"Tom7" ];        NSPredicate *predicate4=[NSPredicate predicateWithFormat:@"name in %@",arrayname];        //是否以某個字符開頭,可以使用和與或        NSPredicate *predicate5=[NSPredicate predicateWithFormat:@"name beginswith 'j'"];        //是否以某個字符結尾,可以使用和與或        NSPredicate *predicate6=[NSPredicate predicateWithFormat:@"name endswith '9'"];        //contains 是否包含某個字符        NSPredicate *predicate7=[NSPredicate predicateWithFormat:@"name contains 'a'"];        //like 類似SQL中的模糊查找        NSPredicate *predicate8=[NSPredicate predicateWithFormat:@"name like '*a*'"];

//方法一:        for (person *p1 in array) {            //返回布爾值,根據布爾值可以判斷符合要求的數據            BOOL result=[predicate evaluateWithObject:p1];            if (result) {                NSLog(@"%@",p1);            }        }        //方法二        //filterUsingPredicate,將過濾后的方法放入原方法中,數組是可變數組        [array filterUsingPredicate:predicate];        for (person *p1 in array) {            NSLog(@"%@",p1);        }        //方法三        //filteredArrayUsingPredicate,將過濾后的結果放入一個新的數組中        NSArray *array1=[array filteredArrayUsingPredicate:predicate8];        for (person *p1 in array1) {            NSLog(@"%@",p1);        }