PAT BASIC 1012

2019-11-11 02:05:14

字體：大中小

來源：轉載

供稿：網友

思路：

這個題大概是想考switch的使用吧，沒什么難點，如果想知道cout怎么保留一位小數，去看一下我的博客

然后這個題的樣例2我覺得有問題，明明有5，不能說是沒有。既然樣例這么理解那就按照他來。

代碼：

#include<iostream>#include<iomanip>using namespace std;int main(){ int state[5] = { 0 }; int a1 = 0, a2 = 0, a3 = 0, a5 = 0; double a4 = 0; int flag2 = 1, num4 = 0; int n, i, j, num; cin >> n; for (i = 0; i < n; i++) { cin >> num; switch (num%5) { case 0: if (num % 2 == 0) { state[0] = 1; a1 += num; } break; case 1: state[1] = 1; a2 = a2 + flag2*num; flag2 = -1 * flag2; break; case 2: state[2] = 1; a3++; break; case 3: state[3] = 1; a4 = a4 + num; num4++; break; case 4: state[4] = 1; if (num > a5) a5 = num; break; default: break; } } cout.setf(ios::fixed); a4 = a4 / num4; if (state[0]) cout << a1 << " "; else cout << "N "; if (state[1]) cout << a2 << " "; else cout << "N "; if (state[2]) cout << a3 << " "; else cout << "N "; if (state[3]) cout << fixed << setPRecision(1) << a4 << " "; else cout << "N "; if (state[4]) cout << a5; else cout << "N"; //while (1) //{ //} return 0;}

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