Given scores of N athletes, find their relative ranks and the people with the top three highest scores, who will be awarded medals: "Gold Medal", "Silver Medal" and "Bronze Medal".

Example 1:

Input: [5, 4, 3, 2, 1]Output: ["Gold Medal", "Silver Medal", "Bronze Medal", "4", "5"]Explanation: The first three athletes got the top three highest scores, so they got "Gold Medal", "Silver Medal" and "Bronze Medal". For the left two athletes, you just need to output their relative ranks according to their scores.
Note:
N is a positive integer and won't exceed 10,000.All the scores of athletes are guaranteed to be unique.
Subscribe to see which companies asked this question.
給每一個數(shù)一個排名，前三名是金銀銅。這是排序的問題。將原序列的每個數(shù)的鍵值和值組成pair，然后按值從大到小排序。最后按順序給排名就行了。
代碼：
class Solution{public:	vector<string> findRelativeRanks(vector<int>& nums)	{		vector<pair<int, int> > vec;		vector<string> res(nums.size());		string ranks[3] = {"Gold Medal", "Silver Medal", "Bronze Medal"};		for(int i = 0; i < nums.size(); ++i) 			vec.push_back(pair<int, int>(i, nums[i]));		auto cmp = [](const pair<int, int>& p1, const pair<int, int>& p2) { return p1.second > p2.second; };		sort(vec.begin(), vec.end(), cmp);		for(int i = 0; i < nums.size(); ++i)		{			if(i < 3) res[vec[i].first] = ranks[i];			else res[vec[i].first] = to_string(i+1);		}		return res;	}};