#include <iostream>using namespace std;void PRint_subset(int n, int * A, int cur){    for(int i = 0; i < cur; i++)            //只要其中有數(shù)，就需要輸出        cout<<A[i];    cout<<endl;    int s = cur ? A[cur - 1] + 1 : 0;     //如果cur不等于零，將由已有序列中的最大的加一開始遍歷    for(int i = s; i < n; i++){        A[cur] = i;        print_subset(n, A, cur + 1);    }}int main(){    int A[1000];    int n;    cin>>n;    for(int i = 0; i < n; i++){        cin>>A[i];    }    print_subset(n, A, 0);    return 0;}2、位向量法
#include <iostream>using namespace std;void print_subset(int n, int * B, int cur){    if(cur == n){        for(int i = 0; i < cur; i++){            if(B[i]) cout<<i;        }        cout<<endl;        return;    }    B[cur] = 1;                          //此位存在標(biāo)1    print_subset(n, B, cur + 1);    B[cur] = 0;                          //此位不存在標(biāo)0    print_subset(n, B, cur + 1);}int main(){    int n;    cin>>n;    int B[1000] = {0};    print_subset(n, B, 0);    return 0;}3、二進(jìn)制法與按位輸出差不多
#include <stdio.h>void print_subset(int n, int s){    for(int i = 0; i < n; i++){        if(s & (1<<i)) printf("%d", i);    }    printf("/n");}int main(){    int n;    scanf("%d", &n);    for(int i = 0; i < (1<<n); i++){        print_subset(n, i);    }    return 0;}