Calculate a + b and output the sum in standard format -- that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

-1000000 9Sample Output
-999,991
// 題目分析：
沒有難點，可以有多種實現(xiàn)方法，此處練習堆棧操作
// 代碼
#include <iostream>#include <string>#include <stack>using namespace std;int main(){	int a,b;	cin>>a>>b;	int c=a+b;	if(c<0){		c=-c;		cout<<'-';	}else if(c==0){		cout<<0;		return 0;	}	stack<char> s;	int count=0;//計數(shù)器	while(c!=0){		if(count%3==0&&count!=0){			s.push(',');		}		s.push(c%10+'0');		count++;		c/=10;	}	while(!s.empty()){		cout<<s.top();		s.pop();	}	system("pause");	return 0;}
// 結(jié)果